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CBSE Class 11-science Answered

Calculate mass of 50% pure limestone required to react completely with 20ml 1Molar HCL 

Asked by arunavamitra50 | 19 Aug, 2018, 08:14: PM
Expert Answer
Given colon

Molarity space of space HCl space equals 1 space straight M

Volume space of space HCl space equals 20 space ml

Molarity space equals fraction numerator No. space of space moles over denominator Volume space in space litre end fraction

No. space of space moles space space equals Molarity over Volume

space space space space space space space space space space space space space space space space space space space space space equals 1 over 20

No. space of space moles space straight n space equals space 0.05 space mole

No. space of space moles space equals fraction numerator Weight over denominator Molecular space weight end fraction

Mass space of space HCl space space equals 0.05 cross times 36.5

space space space space space space space space space space space space space space space space space space space space equals 1.825 space straight g
The space chemical space equation space is space

CaCO subscript 3 plus 2 HCl rightwards arrow space CaCl subscript 2 space plus space straight H subscript 2 straight O plus CO subscript 2

So comma space 73 space straight g space of space HCl space requires space 100 space gm space of space CaCO subscript 3
1 space straight g space of space HCl space will space require space equals fraction numerator 1 cross times 100 over denominator 73 end fraction

space space space space space space space space space space space space space space space space space space space space space equals 1.36 space gm space of space CaCO subscript 3

So comma space 1.825 space straight g space of space HCl space will space require space space equals fraction numerator 1.825 cross times 1.36 over denominator 1 end fraction space

space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 2.5 space straight g space space of space CaCO subscript 3

It space is space given space that space the space limestone space is space 50 percent sign pure comma

So space 2.5 cross times 2 space straight g space of space CaCO subscript 3 space is space required space to space eact space completely space with space 20 space ml space 1 Molar space HCl space

5 space straight g space of space CaCO subscript 3 space is space required space to space eact space completely space with space 20 space ml space 1 Molar space HCl space
5 g of 50% pure limestone required to react completely with 20ml 1Molar HCl.
 
Answered by Varsha | 20 Aug, 2018, 03:49: PM
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