At what partial
pressure oxygen will have a solubility of 0.06 gram per litre in water at 293 Kelvin Henry's law constant of oxygen in water at 303 kelvin is 46.82 k bar assume the density of the solution to the same as that of water
Asked by pandeyn1604
| 29th May, 2019,
09:16: AM
Expert Answer:
Given:
Solubility of O2 = 0.06 gram/litre
KH = 46.82 kbar
= 46.82 × 103 bar
Mass of 1 L of water = 1000 gm
Mass of solvent = 1000 - 0.06
≈ 1000 gm
No. of moles of water
No. of moles of O2
Mole fraction of O2
We have,
PO2 = KH × ΧO2
= 46.82 × 103 × 6.75 × 10−5
= 3.160 bar
The partial pressure of O2 is 3.16 bar.
PO2 = KH × ΧO2
= 46.82 × 103 × 6.75 × 10−5
= 3.160 bar
The partial pressure of O2 is 3.16 bar.
Answered by Varsha
| 29th May, 2019,
12:01: PM
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