AP
Asked by | 27th Sep, 2009, 12:11: PM
let a and d be the first term and the common diff of the A.P.
Tm=1/n
and
Tn=1/m... given
so
a+(m-1)d=1/n...(i)
a+(n-1)d=1/m...(ii)
solving (i) and (ii) we get
a=1/mn
d=1/mn
now
Tmn=a+(mn-1)d
=1/mn+[(mn-1)*(1/mn)]
=1/mn+[1-(1/mn)]
=1
Answered by | 27th Sep, 2009, 02:09: PM
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