an iron rod 4m long and 0.5cm2 in cross section stretches 1mm when a mass of 225kg is hung from its lower end . calculate youngs modolus of iron?
Asked by sammy123 | 19th Mar, 2015, 06:42: PM
" /> Young ' s modolus , Y = F A ∆ L L ∆ L L = 1 × 10 - 3 m 4 m = 0 . 25 × 10 - 3 m F = 225 kg × 9 . 8 m / s 2 = 2205 N Given that m = 0 . 5 × 10 - 4 m 2 Substituting the values we get : Y = 2205 0 . 5 × 10 - 4 m 2 0 . 25 × 10 - 3 m = 1 . 76 × 10 11 N / m 2
Answered by Yashvanti Jain | 11th Dec, 2017, 07:23: PM
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