A toy rocket of mass 0.1kg has a small fuel of mass 0.2kg which it burns in 3s Starting from rest on a horizontal smooth track it gets a speed of 20 m/s after the fuel is burned out.

Asked by Arpit Panda | 14th Nov, 2010, 01:38: PM

Expert Answer:

Dear student
Pls. post each query seperately.
here, u = 20m/s , rate of consumption of fuel  dm/dt  = (1/30) kg/s
the thurst on the rocket , F = u ( dm/dt) = 20 x (1/30) N = 2/3 N
We hope this clarifies your doubt.
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Answered by  | 17th Nov, 2010, 03:36: PM

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