CBSE Class 11-science Answered
A particle starting from the corner start moving with constant velocity 1m/s along the diagonal of a cube. Taking the corner as origin, finf the position of the partice after 1 sec.
Asked by shaikh.farid25 | 26 May, 2018, 09:11: AM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/0f08076ef917ae289930d9902ef06e445b0b94701dad18.98367417May2801.png)
The coordinate system is shown in figure. Let the position of the particle after 1 sec is (x,y,z).
distance travelled from origin is ![begin mathsize 12px style square root of x squared plus y squared plus z squared end root space space equals space 1 space m end style](https://images.topperlearning.com/topper/tinymce/cache/b616df84545bfca3972cfabaabb59b66.png)
![begin mathsize 12px style square root of x squared plus y squared plus z squared end root space space equals space 1 space m end style](https://images.topperlearning.com/topper/tinymce/cache/b616df84545bfca3972cfabaabb59b66.png)
hence x = y = z = 1/√3
coordinate of paticle after 1 sec is (1/√3, 1/√3, 1/√3)
Answered by Thiyagarajan K | 28 May, 2018, 11:06: AM
Concept Videos
CBSE 11-science - Physics
Asked by barunmandal12345jmt | 11 Jul, 2024, 16:23: PM
CBSE 11-science - Physics
Asked by chandinichauhai | 10 Jul, 2024, 23:32: PM
CBSE 11-science - Physics
Asked by sulthanxx | 08 Jul, 2024, 19:29: PM
CBSE 11-science - Physics
Asked by bhuvana.s3001 | 21 Jun, 2024, 23:21: PM
CBSE 11-science - Physics
Asked by contact.asmita03 | 15 Jun, 2024, 11:51: AM
CBSE 11-science - Physics
Asked by parthjain2448 | 12 Jun, 2024, 15:53: PM
CBSE 11-science - Physics
Asked by kaivalyaam | 12 Jun, 2024, 03:24: AM
CBSE 11-science - Physics
Asked by tkanmani022 | 11 Jun, 2024, 20:50: PM
CBSE 11-science - Physics
Asked by duraisamysteephen | 08 Jun, 2024, 12:32: PM