Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

A particle is at x= -10m at t= 1 sec. and moving with the velocity of 10m/s..particle is found at x=18m at t=3sec. find Acceleration of particle and position of particle at t=5sec.
Asked by anandprashant2022 | 21 Jul, 2022, 10:52: PM
Expert Answer
It is assumed the motion is under uniform acceleration

Displacement S made by the particle from t = 1 s  to t = 3 s is given as
 
S = 10 - (-18) = 28 m
 
Displacement S made in a time duration Δt is given as
 
S = ( u × Δt ) + [ (1/2) × a × ( Δt )2 ]
 
where u = 10 m/s is initial speed and a is acceleration
 
Hence by substituting values in above expression, we get
 
28 = ( 10 × 2 ) + [ (1/2) × a × 4 ]
 
we get acceleration a = 4 m/s2 from above expression .
 
Position at t = 5 s is determined from he displacement made from t =3 s to t = 5 s.
 
S = ( 10 × 2 ) + [ (1/2) × 4 × 22 ] = 28 m
 
Postion x at t = 5 s is  ,  x = ( 18 + 28 ) m = 46 m
Answered by Thiyagarajan K | 22 Jul, 2022, 08:53: AM
JEE main - Physics
Asked by mrudhulaprakashmanda844 | 23 Jul, 2022, 10:26: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by sreekarreddypindi | 30 May, 2022, 12:15: PM
ANSWERED BY EXPERT

Start your hassle free Education Franchisee and grow your business!

Know more
×