A parallel plate capacitor with air between the plates have the capacitance of 8pF. What will be the capacitance if the distance between the plates be reduced by half and space between them is filled with a substance of K=6.

Asked by JASKAMAL KAUR | 13th Jun, 2015, 11:24: AM

Expert Answer:

Capacitance of parallel plate air capacitor is given as:
begin mathsize 12px style straight C equals fraction numerator straight epsilon subscript straight o straight A over denominator straight d end fraction space minus negative negative negative negative left parenthesis Equation space 1 right parenthesis Given space that space straight C space equals 8 space pF When space the space distance space between space the space plates space is space reduced space to space half comma space the space distance space between space the space plates space become space straight d over 2 space and space filled space with space straight a space substance space of space dielectrci space constant comma space straight K equals 6 straight C apostrophe equals fraction numerator Kε subscript straight o straight A over denominator begin display style bevelled straight d over 2 end style end fraction straight C apostrophe equals fraction numerator 2 Kε subscript straight o straight A over denominator begin display style straight d end style end fraction space minus negative negative negative left parenthesis Equation space 2 right parenthesis fraction numerator straight C apostrophe over denominator straight C end fraction equals 2 space minus negative negative left parenthesis From space equation space 1 space and space 2 right parenthesis straight C apostrophe equals 2 CK space straight C apostrophe equals 2 cross times 8 cross times 6 straight C apostrophe equals 96 space pF end style

Answered by Yashvanti Jain | 15th Dec, 2017, 11:47: AM