A motor bike initially moving at 18 km/hr accelerates at a rate of 5 m/s2 for 5 s.Calculate: (1)distance covered by it from start (2) the final velocity?

Asked by Vikas | 3rd Jul, 2017, 12:50: PM

Expert Answer:

begin mathsize 12px style Given space data colon
Initial space velocity space of space the space bike space equals space 18 space km divided by straight h space equals space 5 space straight m divided by straight s space
Fianl space velocity space equals space straight v space equals space to space be space calculated
Acceleration space equals space 5 space straight m divided by straight s squared space and space time space equals space 5 space straight s
left parenthesis straight i right parenthesis space We space use space the space equation space straight s space equals space ut space plus space 1 half at squared
Substitute space the space given space values space in space the space above space equation space and space calculate space the space value space of space straight s.
After space calculations comma space it space comes space out space to space be space
straight s space equals space 87.5 space straight m

left parenthesis ii right parenthesis space To space find space the space final space velocity comma space we space use space the space equation space straight v space equals space straight u space plus space at
Substitute space the space values space in space the space baove space equation.
Final space velocity space equals space 30 space straight m divided by straight s end style

Answered by Yashvanti Jain | 3rd Jul, 2017, 01:00: PM