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A metal sphere of mass 200g falls from a height of 5 m. Calculate velocity with which it will strike the ground.g=10m/s-2
Asked by khushdab | 23 Apr, 2020, 02:17: PM
m = 200 g = 0.2 kg
h = 5 m
a = g = 10 m/s2
u = 0 ( as it is going to fall from a rest position)
v =?

By third equation of motion, we know,
v2 - u2 = 2as

As the sphere is falling from height, equation becomes,
v2 - u2 = 2gh

v2 - 0 = 2 × 10× 5

v2 = 100

Thus,
v = 10 m/s

OR

There is one more way to solve this problem,

we have mass, height and acceleration due to gravity.
When the sphere is at height, potnetial energy stored in it is,
P.E. = mgh = 0.2 x 10 x 5 =10 J

When the sphere strikes the ground,
K.E. = 1/2 mv2

Thus, at ground K.E. = P.E.

10 = (1/2) x 0.2 x v2
Solving this,

v2 = 20/0.2 = 100

Thus,
v = 10 m/s

Hence, the velocity with which sphere will hit the ground is 10 m/s

Answered by Shiwani Sawant | 23 Apr, 2020, 07:51: PM

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