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A farmer moves along the boundary of square field of side 10m in 40sec . What will be the magnitude of displacement of farmer at the end of 2 min 20 sec from his initial position?
Asked by kanikathakkar836 | 19 May, 2020, 11:27: PM

Let the initial point of the farmer be point PThe distance covered by the farmer in 40 s is 4 × 10 = 40 m. The total time given: 2 min and 20 s = (2 × 60) + 20 = 140 sSince the farmer moves 40 m in 40 s, therefore in 1 s the farmer covers a distance,Therefore, the distance covered by the farmer in 140 s is:140 × 1 m = 140 m.Thus the number of rotations to cover 140 m along the boundary is:So, the farmer will be at point R after 140 s.So the displacement = PR =  = 14.1 m

Answered by Shiwani Sawant | 20 May, 2020, 12:07: AM

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