A disc of mass 50grams slides with initial velocity =0 down an inclined plane set at an angle 30 degrees with horizontal. After covering 50cm along the horizontal plane, the disc stops. Find the work done by friction over the whole distance,coefficient of friction =0.15
Asked by rhariharan | 6th Dec, 2010, 11:23: PM
Expert Answer:
force of friction = 
where μ = cofficient of friction
and N = normal rection.
Now
work done = force * displacement
= 0.15*0.25 * (.5 m)
= 0.15*0.125 Joules
= 0.01875 J
Answered by | 7th Dec, 2010, 08:36: PM
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