a bullet of mass 50 gms moving with a speed of 500m/s is brougt to rest in 10seconds how much is the work done by stoping force what is the power deliverd by the bullet where does the energy of bullet gone

Asked by shashank pandey | 24th Nov, 2010, 12:00: AM

Expert Answer:

work done = change in kinetic enegy
               = Kf - Ki
negative sign shows that direction of force is opposite to displace ment
               putting m = 50/1000  kg
                          v  = 500 m/s
 we get work done W = 6250 joule
power = W/ time
          = 6250/10  watt
          = 625 watt
 Energy of bullet is converted in heat (and some sound)

Answered by  | 24th Nov, 2010, 12:17: PM

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