CBSE Class 9 Answered
a bullet of mass 50 gms moving with a speed of 500m/s is brougt to rest in 10seconds how much is the work done by stoping force what is the power deliverd by the bullet where does the energy of bullet gone
Asked by shashank pandey | 24 Nov, 2010, 12:00: AM
Expert Answer
work done = change in kinetic enegy
= Kf - Ki
=
negative sign shows that direction of force is opposite to displace ment
putting m = 50/1000 kg
v = 500 m/s
we get work done W = 6250 joule
power = W/ time
= 6250/10 watt
= 625 watt
Energy of bullet is converted in heat (and some sound)
Answered by | 24 Nov, 2010, 12:17: PM
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