a ball is thrown vertically upward with a velocity of 49m/s calculate maximum height attains by the ball

Asked by prachikathuria | 21st Sep, 2021, 02:15: PM

Expert Answer:

Maximum height reached by the ball that is thrown vertically upwards is detrmined by the
equation of motion " v = u2 + (2 a h ) "
 
where v = 0 is final velocity becuse when the reaches maximum height h, its velocity becomes zero ,
u = 49 m/s is initial velocity  and a = -g = -9.8 m/s2 is acceleration due to gravity 
 
Hence we get ,  u2 = 2g h 
 
 h = u2 / 2g =  ( 49 × 49 ) / ( 2 × 9.8 ) = 122.5 m

Answered by Thiyagarajan K | 21st Sep, 2021, 03:04: PM