Request a call back

a ball is thrown vertically upward with a velocity of 49m/s calculate maximum height attains by the ball
Asked by prachikathuria | 21 Sep, 2021, 02:15: PM
Maximum height reached by the ball that is thrown vertically upwards is detrmined by the
equation of motion " v = u2 + (2 a h ) "

where v = 0 is final velocity becuse when the reaches maximum height h, its velocity becomes zero ,
u = 49 m/s is initial velocity  and a = -g = -9.8 m/s2 is acceleration due to gravity

Hence we get ,  u2 = 2g h

h = u2 / 2g =  ( 49 × 49 ) / ( 2 × 9.8 ) = 122.5 m
Answered by Thiyagarajan K | 21 Sep, 2021, 03:04: PM

## Concept Videos

CBSE 9 - Physics
Asked by bablibhati187 | 21 Jun, 2022, 01:48: PM
CBSE 9 - Physics
Asked by npravati227 | 30 May, 2022, 11:04: PM
CBSE 9 - Physics
Asked by chezzlinequeen | 26 May, 2022, 01:03: PM
CBSE 9 - Physics
Asked by urvashi.420 | 10 May, 2022, 05:12: PM
CBSE 9 - Physics
Asked by kumarishubhangi.bhw | 21 Jan, 2022, 11:16: PM
CBSE 9 - Physics
Asked by richaagrawal99.9dgatl | 21 Sep, 2021, 08:16: PM