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A ball is dropped from a building 100m high at the same instance a ball is thrown vertically upwards from the base of the building with what velocity should this ball be thrown so that the two balls collide at a height of. 50 m
Asked by aarushsingh3117 | 06 Jun, 2019, 08:31: AM
time t for dropped ball to reach 50 m distance from top can be obtained from,

S = (1/2)gt2 , where S is the distance 50 m and g is accelertion due to gravity

hence, we have  t = ( 2 S / g )1/2  = (100/9.8)1/2 ≈ 3.2 s

Now in this 3.2 s , the ball thrown from bottom shoud reach 50 m.

we have the relation,  S = u×t - (1/2)×g×t2   ..............................(1)

where S is the ditance 50 m and u is the intial speed of ball thrown from bottom

Substituting the values in eqn.(1), we get u = 31.3 m/s
Answered by Thiyagarajan K | 06 Jun, 2019, 09:10: AM
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