Request a call back

A 9 V battery is connected in series with a resistor .The terminal voltage is found to be 8 V. Current through the circuit is measured as 5 A. What is the internal resistance of the battery?
Asked by ayushmittal2424 | 09 Dec, 2018, 21:45: PM
As we know battery supplied voltage = E - Ir
Where E is the EMF of cell , I is the current passing through battery and r is internal resistance of battery . Putting all the values we get
8=9-5×r
=> r=1/5 =0.2 ohm
Answered by Ankit K | 09 Dec, 2018, 22:29: PM

## Concept Videos

CBSE 12-science - Physics
Asked by guptakartikgupta2 | 16 Jul, 2022, 17:23: PM
CBSE 12-science - Physics
Asked by yashrajgharte24.12dgatl | 18 Aug, 2021, 21:29: PM
CBSE 12-science - Physics
Asked by diyasinha1701 | 31 Jul, 2021, 09:58: AM
CBSE 12-science - Physics
Asked by sulaikhasulu393 | 29 Apr, 2020, 17:17: PM
CBSE 12-science - Physics
Asked by prakriti12oct | 28 Jul, 2019, 23:07: PM
CBSE 12-science - Physics
Asked by rejimoljohn123 | 01 Jan, 2019, 21:08: PM