CBSE Class 11-science Answered
4th sum plz
![question image](https://images.topperlearning.com/topper/new-ate/5038327713243353rps20190127072656.jpg)
Asked by lovemaan5500 | 27 Jan, 2019, 12:25: PM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/439d8863de1fc2da5f9da7c5ae491e8f5c4d688acd98c3.21321402jan2703.png)
Figure shows the arrangement of three 10 g masses placed at the corners of equilateral triangle of side 5 cm.
Since the axis of rotation is passing through one corner where a 10 g mass is placed,
only other two masses are contributing for moment of inertia of the system.
Moment of inertia = 2×10×10-3 × 52 × 10-4 = 5×10-5 kg-m2
Answered by Ankit K | 27 Jan, 2019, 22:10: PM
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