4th sum plz
Asked by lovemaan5500 | 27th Jan, 2019, 12:25: PM
Figure shows the arrangement of three 10 g masses placed at the corners of equilateral triangle of side 5 cm.
Since the axis of rotation is passing through one corner where a 10 g mass is placed,
only other two masses are contributing for moment of inertia of the system.
Moment of inertia = 2×10×10-3 × 52 × 10-4 = 5×10-5 kg-m2
Answered by Ankit K | 27th Jan, 2019, 10:10: PM
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