CBSE Class 12-science Answered

The charge supplied by the battery of 12 V = q × V

                                                             = 1 μF × 12 V = 12 μC

Since the capacitors are then connected in series, 12 μC charge appears on each of the positive plates and -12μC charge on each of the negative plates.

The capacitors are connected as shown below:

The total capacitance is:

The 36 μC charge is distributed as Q₁, Q₂ and Q₃ on the three positive plates and –Q₁, -Q₂ and –Q₃ on the negative plates.

Also, the three positive terminals are now at the same common potential and the three negative plates are also at the same potential.

Let the potential difference across each capacitor be V.

Then,

Q₁ = (2μF)V