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CBSE Class 11-science Answered

18th?
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Asked by smanishkumar2002 | 04 Aug, 2018, 08:35: PM
answered-by-expert Expert Answer
According to the condition of pair of straight line
begin mathsize 16px style open vertical bar table row straight a straight h straight g row straight h straight b straight f row straight g straight f straight c end table close vertical bar equals 0 Comparing space with space standard space form space ax squared plus by squared plus 2 hxy plus 2 gx plus 2 fy plus straight c equals 0 straight a equals 1 comma space straight b equals straight lambda comma space straight h equals fraction numerator negative 3 over denominator 2 end fraction comma space straight g equals 3 over 2 comma space straight f equals fraction numerator negative 5 over denominator 2 end fraction comma space straight c equals 2 open vertical bar table row 1 cell fraction numerator negative 3 over denominator 2 end fraction end cell cell 3 over 2 end cell row cell fraction numerator negative 3 over denominator 2 end fraction end cell straight lambda cell fraction numerator negative 5 over denominator 2 end fraction end cell row cell 3 over 2 end cell cell fraction numerator negative 5 over denominator 2 end fraction end cell 2 end table close vertical bar equals 0 1 half cross times 1 half cross times 1 half open vertical bar table row 2 cell negative 3 end cell 3 row cell negative 3 end cell cell 2 straight lambda end cell cell negative 5 end cell row 3 cell negative 5 end cell 4 end table close vertical bar equals 0 space space space space space space space space space taking space 1 half space common space from space each space row open vertical bar table row 2 cell negative 3 end cell 3 row cell negative 3 end cell cell 2 straight lambda end cell cell negative 5 end cell row 3 cell negative 5 end cell 4 end table close vertical bar equals 0 Solving space this space we space get space straight lambda equals 2 end style
Answered by Sneha shidid | 06 Aug, 2018, 11:12: AM

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