13.4 g of sample of unstable hydrated salt Na2So4.xh2O was found to contain 6.3 g of h20. the no. of molecules of water of crystallization is
Asked by vedant sharma | 30th Oct, 2014, 03:47: PM
Expert Answer:
The molar mass of the salt is m(Na2SO4* xH2O) = 2*23+32+16*4 + x (2 + 16) = 142 + x*18 [g/mol]
Then let's construct the proportion:
13.4 / 6.3 = (142 + 18x)/18x
13.4 * 18x = (142 + 18x) * 6.3
241.2x = 894.6 + 113.4x
127.8x = 894.6
x = 7
Na2SO4* 7H2O
Then let's construct the proportion:
13.4 / 6.3 = (142 + 18x)/18x
13.4 * 18x = (142 + 18x) * 6.3
241.2x = 894.6 + 113.4x
127.8x = 894.6
x = 7
Na2SO4* 7H2O
Answered by Prachi Sawant | 31st Oct, 2014, 09:44: AM
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