CBSE Class 10 Answered
While doing an activity Suraj found that the height of the image became 1 / (4 ^ (th)) of the height of the object when it is placed in front of the secondary mirror Then find the nature position and size ofthe image formed.
Asked by swetalinasamantaray022 | 14 Jan, 2023, 10:47: PM
Expert Answer
It is not known what is meant by secondary mirror.
If magnification is positive and its magnitude is (1/4) , then the mirror is convex mirror.
Nature of image :- virtual and erect
size :- 1/4 of size of object ( given )
Position :- v/u = 1/4
where v is mirror-to-image distance and u is mirror-to-object distance
Hence image is formed behind the mirror at a distance (1/4)th of mirror-to-object distance u
Answered by Thiyagarajan K | 15 Jan, 2023, 10:41: AM
CBSE 10 - Science
Asked by umaambiger87 | 07 Feb, 2024, 10:41: AM
ANSWERED BY EXPERTCBSE 10 - Science
Asked by samudurai1986 | 26 Nov, 2023, 06:55: PM
ANSWERED BY EXPERTCBSE 10 - Science
Asked by princepatel82768 | 08 Nov, 2023, 09:25: PM
ANSWERED BY EXPERTCBSE 10 - Science
Asked by priyanshdhiman2008 | 16 Mar, 2023, 07:25: PM
ANSWERED BY EXPERTCBSE 10 - Science
Asked by swetalinasamantaray022 | 14 Jan, 2023, 10:47: PM
ANSWERED BY EXPERTCBSE 10 - Science
Asked by sadiqfayaz07 | 07 Jan, 2023, 08:31: PM
ANSWERED BY EXPERTCBSE 10 - Science
Asked by tammapadmavathi7 | 24 Dec, 2022, 02:08: PM
ANSWERED BY EXPERTCBSE 10 - Science
Asked by rupalidhaigude7 | 28 Dec, 2019, 09:28: AM
ANSWERED BY EXPERT
