CBSE Class 10 Answered
While doing an activity Suraj found that the height of the image became 1 / (4 ^ (th)) of the height of the object when it is placed in front of the secondary mirror Then find the nature position and size ofthe image formed.
Asked by swetalinasamantaray022 | 14 Jan, 2023, 10:47: PM
Expert Answer
It is not known what is meant by secondary mirror.
If magnification is positive and its magnitude is (1/4) , then the mirror is convex mirror.
Nature of image :- virtual and erect
size :- 1/4 of size of object ( given )
Position :- v/u = 1/4
where v is mirror-to-image distance and u is mirror-to-object distance
Hence image is formed behind the mirror at a distance (1/4)th of mirror-to-object distance u
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