CBSE Class 10 Answered
an object of height 5 cm is placed at a distance of 20 cm infront of a convex mirror of radius of curvature 30cm find the position and nature of image
Asked by umaambiger87 | 07 Feb, 2024, 10:41: AM
Radius R of convex mirror, R = +30 cm ;
Focal length f of convex mirror , f = R/2 = + 15 cm
Mirror equation related to mirror-to-object distance u and mirro-to-image distance v is
By cartesian sign convention u = -20 cm
Hence , we get
from above expression, we get v = 60/7 cm = 8.6 cm
we get v positive, hence image is formed 8.6 cm behind the pole of mirror .
Image is virtual .
magnification of image = -v/u = -8.6/(-20) = 0.43 .
Since magnification is less than one and positive, image is erect and diminished.
Answered by Thiyagarajan K | 08 Feb, 2024, 11:55: AM
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