CBSE Class 11-science Answered
solve this question
Asked by suchananag2002 | 12 Sep, 2019, 06:52: PM
Expert Answer
Friction gives retardation that equals (μ × g ) , where μ is friction coefficient and g is acceleration due to gravity.
if the box started sliding with initial speed u and stopped after 2 s, so that final speed is zero.
we get initial speed from, 0 = u - (μg)2 or u = 2μg
Let us use the formula " S = ut -(1/2)at2 " with S =1, u = 2μg and a = μg
then we have, 1 = (2μg)2 - (1/2)(μg)4 or 2μg = 1 or μ = 1/(2g)
if we use g = 10, then μ = 1/20 = 0.05
Answered by Thiyagarajan K | 12 Sep, 2019, 08:43: PM
CBSE 11-science - Physics
Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sy123946 | 07 Apr, 2024, 04:23: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
ANSWERED BY EXPERT
