CBSE - XII Science - Chemistry - The Solid State
KF has NaCl sturcture . What is distance between K+ and F- in KF if density is 2.48 gm cm-3.
(Molar mass of KF = 58 g mol-1).
d=zXM / a3XNa = 4 X58 / a3X6.02 X1023 = 2.48gm cm-3.
a3 = 155X10-24 cm
a = 5.4 X10 -8cm
dist btw K+ and F- a/2 as it is rock salt structure. 2.7 X 10-8cm
Note: This numerical is from the old course in CBSE it is not in syllabus now.
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