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SOLID STATE

Asked by 23rd February 2008, 10:28 AM
Answered by Expert
Answer:

KF has NaCl sturcture . What is distance between K+ and F- in KF if density is 2.48 gm cm-3.

(Molar mass of KF = 58 g mol-1).

d=zXM / a3XNa = 4 X58 / a3X6.02 X1023 = 2.48gm cm-3.

a3 = 155X10-24 cm

a = 5.4 X10 -8cm

dist btw K+ and F-  a/2 as it is rock salt structure. 2.7 X 10-8cm

Note: This numerical is from the old course in CBSE it is not in syllabus now.

Answered by Expert 8th December 2017, 5:30 PM
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