CBSE Class 12-science Answered
Silver crystallizes in fcc lattice. If edge length is 4.07x10-8 cm and density is 10.5 g cm3, calculate the atomic mass of silver.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Identify given: in fcc, z= 4, a = 4.05x 10-8 cm , d = 10.5 g cm3, NA = 6.022 x 1023atoms
M =?d = zM / a3NA.
10.5 g cm3= 4xM / (4.05x 10-8 cm)3x 6.022 x 1023atoms = 107.8u
Answered by | 04 Jun, 2014, 03:23: PM
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