CBSE Class 11-science Answered
Pls solve it.(Question 5)
Asked by pb_ckt | 06 Jun, 2019, 09:24: PM
Expert Answer
if the bullet travelling with speed 160 m/s is stopped in 0.02 s ,
then retardation a is obtained from relation v = u - a×t ,
where v is final speed which is zero, u is initial speed and t is time.
retardation = u/t = 160/0.02 = 8000 m/s2
distance S travelled in wooden plank is obtained from the relation v2 = u2 - ( 2 a S ) ,
hence S = u2 / (2a) = 160×160 /(2×8000) = 1.6 m
Answered by Thiyagarajan K | 06 Jun, 2019, 10:29: PM
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