CBSE Class 11-science Answered
Pls solve it.
Asked by pb_ckt | 07 Jun, 2019, 01:47: PM
Expert Answer
position x = t2 - 3t ...........................(1)
since position is expressed as a function of t, time of maximum displacement xmax is obtained by equating dx/dt to zero,
dx/dt = 2t - 3 = 0 or at t = 3/2 we have maximum displacement . Maximum displacement xmax = (1.5)2 - 3(1.5) = -2.25
at t = 3 s, displacement = 32 - 3(3) = 0
hence from t=0 to t=3 s particle has moved a distance 2.25 m in negative direction then moved to position x=0.
Hence total distance moved in 3 s is 4.5 m . Hence average speed = distance/time = 4.5/3 = 3/2 m/s
Answered by Thiyagarajan K | 08 Jun, 2019, 03:20: PM
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