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Asked by Balbir | 02 Oct, 2019, 12:04: AM
answered-by-expert Expert Answer
Electrolysis of BaSO4 -
 
BaSO subscript 4 space space end subscript left right double arrow Ba to the power of plus 2 end exponent space plus space SO subscript 4 to the power of negative 2 end exponent straight K subscript sp equals open square brackets Ba to the power of plus 2 end exponent close square brackets open square brackets SO subscript 4 to the power of negative 2 end exponent close square brackets Solubility equals fraction numerator straight k cross times 1000 over denominator logical and end fraction equals fraction numerator 3.06 cross times 10 to the power of negative 6 space end exponent cross times 1000 over denominator 1.53 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 2 cross times 10 to the power of negative 3 end exponent straight K subscript sp space space space end subscript equals space open square brackets Ba to the power of plus 2 end exponent close square brackets open square brackets SO subscript 4 to the power of negative 2 end exponent close square brackets space space space space space space space space equals open square brackets 2 cross times 10 to the power of negative 3 end exponent close square brackets squared space space space space space space space space equals 4 cross times 10 to the power of negative 6 end exponent
Answered by Ravi | 04 Oct, 2019, 05:02: PM

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