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How many gram of Cu will be obtained by passing 4.5 ampere current thrugh 1 litre 0.6M CuCl2 aqueous solution by dipping inert electrodes for 1 hour? what will be the change in concentration ?
Asked by aarchi80 | 30 Jun, 2021, 03:37: PM
answered-by-expert Expert Answer
straight I equals 4 straight A comma space straight t equals 1 space hour equals 60 space minutes equals 60 cross times 60 equals 3600 space seconds Weight space of space copper space that space can space be space deposited space by space 96500 space straight C equals fraction numerator 63.54 over denominator 2 end fraction equals 31.27 space straight g straight Q equals It straight Q equals 4.5 cross times 60 cross times 60 straight Q equals 16200 space straight F Weight space of space Copper space that space is space deposited space by space 16200 straight F space fraction numerator 31.77 cross times 16200 over denominator 96500 end fraction equals 5.33 space straight g Moles space of space Cu equals fraction numerator 5.33 over denominator 63.54 end fraction equals 0.0838 space Moles space of space Cu equals 0.0838 space Moles space will space be space same space as space CuCl subscript 2 space moles. Solution space volume space is space space 1 space litre So comma space Change space in space concentration equals 0.0838 space mole divided by straight L
Answered by Ravi | 30 Jun, 2021, 05:00: PM

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