CBSE Class 11-science Answered
please answer this
Asked by Prashant DIGHE | 04 Mar, 2020, 10:03: PM
Expert Answer
After closing the switch, both capacitors are in series, hence equivalent capacitance becomes 0.5 μf .
Hence charge on each capcitor will be ( 10 V × 0.5 μf ) = 5 μC.
Hence C1 has already 10 μC , charge of 5 μC will pass through battery to charge other capacitor C2
Hence wrokdone by battery = 5 μC × 10 V = 50 μJ
Answered by Thiyagarajan K | 05 Mar, 2020, 11:16: AM
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