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NEET Class neet Answered

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Asked by Prashant DIGHE | 07 Jan, 2020, 10:06: PM
answered-by-expert Expert Answer
P1o = 10 Torr
P =9 Torr
 
 
fraction numerator straight P subscript 1 to the power of straight o minus straight P subscript straight s over denominator straight P to the power of straight o subscript 2 end fraction equals straight n subscript straight A over straight n subscript straight A space plus straight n subscript straight B end subscript
1 over 10 equals fraction numerator 1 divided by straight x over denominator 1 divided by straight x space plus 1 divided by 10 end fraction
1 over 10 equals fraction numerator 1 divided by straight x over denominator 1 divided by straight x space plus space 1 divided by 10 end fraction
1 over 10 equals fraction numerator 10 over denominator 10 plus straight x end fraction
10 plus straight x equals 100
straight x equals 90 space amu
Answered by Ravi | 08 Jan, 2020, 02:32: PM
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