NEET Class neet Answered

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Asked by prakriti12oct | 28 Apr, 2020, 01:31: AM

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As space given comma 2 straight H subscript 2 SO subscript 4 space rightwards arrow with blank on top space straight H subscript 2 straight S subscript 2 straight O subscript 8 space plus space straight H subscript 2 2 straight H subscript 2 straight O rightwards arrow with blank on top space 2 straight H subscript 2 space plus space straight O subscript 2 therefore space fraction numerator No. space of space eq. of space straight O subscript 2 space plus space No. space of space eq. space of space straight H subscript 2 straight S subscript 2 straight O subscript 8 over denominator Anode space products end fraction space equals space fraction numerator No. space of space eq. of space straight H subscript 2 over denominator cathode space product end fraction eq. space of space straight O subscript 2 equals fraction numerator 2.35 over denominator 5.6 end fraction space........................... open parentheses because space 1 straight g space of space eq. space straight O subscript 2 space equals space 8 straight g space straight O subscript 2 space equals space 5.6 space litre space straight O subscript 2 space at space STP close parentheses eq. space of space straight H subscript 2 equals fraction numerator 9.27 over denominator 11.2 end fraction............................. open parentheses because 1 space straight g space of space straight H subscript 2 space equals space 1 straight g space of space straight H subscript 2 space end subscript equals space 11.2 space litre space straight H subscript 2 space at space STP close parentheses therefore space straight g. space eq. space of space straight H subscript 2 straight S subscript 2 straight O subscript 8 space equals fraction numerator 9.27 over denominator 11.2 end fraction space minus space fraction numerator 2.35 over denominator 5.6 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space fraction numerator 9.72 space minus 4.7 over denominator 11.2 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 5.02 over denominator 11.2 space end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.448

Hence option A is the correct option.

Answered by Ramandeep | 28 Apr, 2020, 01:14: PM

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