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Asked by deepakudgiri29 4th January 2019, 5:13 PM
Answered by Expert
Answer:
Case I :
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space CH subscript 3 COONa space plus space HCl space space space space rightwards arrow with blank on top space space CH subscript 3 COOH space plus space NaCl space
Initial space moles space space space space space space space space space space space space space space space space space space space 1 space space space space space space space space space space space space space space space space space space space space space 1 space space space space space space space space space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space 0
Initial space moles space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space space space space space space space space space space space 1 space space space space space space space space space space space space space space space space space space space space 1

therefore space left square bracket space CH subscript 3 COOH right square bracket space equals space open parentheses 1 over 1 close parentheses space equals space space 1 thin space straight M
therefore space left square bracket space straight H to the power of plus equals cα space equals space straight c square root of open parentheses straight K subscript straight a divided by straight c close parentheses end root space equals space square root of open parentheses straight K subscript straight a. straight c close parentheses end root space equals square root of straight K subscript straight a end root space space space space space space space space space space............ left parenthesis because straight c space equals space 1 right parenthesis

or space pH subscript 1 space equals space minus 1 half space log space straight K subscript straight a space space space space space space space space space space space space space space space space space space space space space space................................ left parenthesis space straight I space right parenthesis

 
Case II :
 
 
space space space space space space space space space space space space CH subscript 3 COONa plus space CH subscript 3 COOH
space space space space space space space space space space space space space space space space space space space space space space 1 space straight M space space space space space space space space space space space space space space space space space space space space space space space 1 space straight M

This space is space straight a space buffer space and space thus comma

pH subscript 2 space equals space minus space log space straight K subscript straight a space plus space log salt over acid space equals space minus log space straight K subscript straight a space plus space log space 1 over 1
pH subscript 2 space equals space minus space log space straight K subscript straight a space.................................................. space left parenthesis space II space right parenthesis

By space left parenthesis space straight I space right parenthesis space and space left parenthesis space II right parenthesis space comma space we space get comma

bold pH subscript bold 1 bold colon bold space bold pH subscript bold 2 bold space bold colon bold colon bold space bold 1 bold space bold colon bold space bold 2
Answered by Expert 7th January 2019, 11:49 AM
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