Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days


Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number


Mon to Sat - 11 AM to 8 PM


Asked by 29th February 2008, 11:30 PM
Answered by Expert


Heptance and octane form an ideal solution at 373 K, The vapour pressures of the pure liquids at this terperature

are 105.2 KPa and 46.8 KPa respectively. If the solution contains 25g of heptance and 28.5g of octane, calculate

(i) vapour pressure exerted by heptane

(ii) vapour pressure exerted by solution

(iii) mole fraction of octane in the vapour phase

apply raoults law p1=105.2 X mole fraction of heptane

p2 = 46.8 X mole fraction of octane solution= p1 +p2

Answered by Expert 2nd March 2008, 6:43 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp