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CBSE Class 12-science Answered

A 10% solution of urea ( molar mass 60) is found to be isotonic with a 5% solution of an unknown non-electrolyte substance.The molecular mass of unknown substance is (a) 40% (b) 50% (c) 45% (d) 30%
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Asked by kaushikmisty07 | 31 Dec, 2023, 11:42: AM
answered-by-expert Expert Answer

Dear Student,

We know that, osmotic pressure is represented by,

Π = CRT

Isotonic so, Π of urea solution = Π of x solution

C1RT = C2RT

C1 = C2

1 dm3 = 1L

C of urea = 10 g / 60 g      ( mol wt of urea = 60 g)

C of x = (5 × 1000) / (mol. wt of x × 100)

10 / 60 =  (5 × 1000) / (mol. wt of x × 100)

Solving,

Mol. wt of x = 300 g

Answered by | 31 Dec, 2023, 04:20: PM

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