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120 GM Naoh is dissolved in 3dm³ aqcus solution find out its molarity and normality
Asked by sameerteli003 | 08 Apr, 2024, 11:48: PM

Dear Student,

Molarity = moles of solute / volume of solution in dm3

Molar mass of NaOH = 40 g/mol

Hence, the number of moles of NaOH

Moles = Mass / Molar mass = 120 g / 40 g/mol = 3 moles

Molarity = 3 moles / 3 dm3  = 1 M

Hence, the molarity of the NaOH solution is 1 M.

Normality = Number of equivalents in the formula unit of the solute × Molarity

N = nM

The equivalent factor of NaOH is 1 since it provides 1 mole of hydroxide ions (OH-) per mole of NaOH.

N = 1 M × 1 = 1 N

Hence, the normality of the NaOH solution is 1 N.

Answered by | 10 Apr, 2024, 09:46: AM

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