CBSE Class 12-science Answered

Dear Student,

Molarity = moles of solute / volume of solution in dm³

Molar mass of NaOH = 40 g/mol 

Hence, the number of moles of NaOH 

Moles = Mass / Molar mass = 120 g / 40 g/mol = 3 moles

Molarity = 3 moles / 3 dm³  = 1 M

Hence, the molarity of the NaOH solution is 1 M.

Normality = Number of equivalents in the formula unit of the solute × Molarity

N = nM

The equivalent factor of NaOH is 1 since it provides 1 mole of hydroxide ions (OH^-) per mole of NaOH.

N = 1 M × 1 = 1 N

Hence, the normality of the NaOH solution is 1 N.