CBSE Class 11-science Answered
How long after the beginning of motion is the displacement of a harmonically oscillating particle equal to one half its its amplitude if the period is24s and particle starts from rest.
Asked by aradhanarishab | 25 Nov, 2018, 11:11: PM
Expert Answer
Displacement x of SHM, x = a sin( ωt ) .....................(1)
where a is amplitude, ω is angular frequency which is given by ω = 2π/T where T is period of SHM and t is time
if displacement x is half of amplitude, then time taken is calculated using eqn.(1) as given below
(a/2) = a sin [ (2π/ 24) t ]
hence ( π/12 )t = sin-1(1/2) = π/6 or t = 2 s
Answered by Thiyagarajan K | 26 Nov, 2018, 12:01: AM
CBSE 11-science - Physics
Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sy123946 | 07 Apr, 2024, 04:23: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
ANSWERED BY EXPERT
