CBSE Class 11-science Answered
Four identical bricks are kept over one another in such a way that a part of each brick is projected out of the brick below it.For equilibrium of the system, how much of the three upper bricks can be extended out?
Asked by suchananag2002 | 08 Sep, 2019, 10:59: PM
Expert Answer
Let the semi length of each brick is l cm and mass of each brick is m kg.
Let O be the centre of mass of bottom most brick.
Let l1 , l2 and l3 are the horizontal displacements given to each block as shown in figure.
Horizontal position l' of centre of mass of system of combined three bricks placed on the bottom most brick
with the above mentioned displacements is given by
l' = ( m l1 + m l2 + m l3 )/(3m) .........................(1)
For equilibrium, l' < l ......................(2)
Hence, [ ( m l1 + m l2 + m l3 )/(3m) ] < l or ( l1 + l2 + l3 ) < 3l .............................. (3)
In addition to the above condition (3), each extension should be less than l for equilibrium as shown in figure
i.e. l1 < l , l2 < l and l3 < l .............................(4)
Answered by Thiyagarajan K | 09 Sep, 2019, 10:10: AM
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