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CBSE Class 12-science Answered

Calculate the approximate number of unit cells Present in 1gm of Gold. Gold crystallizes in FCC @ AT mass of gold = 197u.  ?
Asked by vikmandal000 | 11 Feb, 2016, 03:40: PM
answered-by-expert Expert Answer
1 space mole space of space gold space equals space 197 space straight g space equals space 6.02 cross times 10 to the power of 23 Hence comma space No. space of space atoms space present space in space 1 space straight g space og space gold space equals space fraction numerator 6.02 cross times 10 to the power of 23 over denominator 197 end fraction As space face minus centered space cubic space unit space cell space contains space 4 space atoms comma therefore. space number space of space unit space cells space present space equals space fraction numerator 6.02 cross times 10 to the power of 23 over denominator 197 cross times 4 end fraction space equals space 7.64 cross times 10 to the power of 20
Answered by Prachi Sawant | 12 Feb, 2016, 02:43: PM

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CBSE 12-science - Chemistry
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CBSE 12-science - Chemistry
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