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An engine pumps a fluid of density 1200 kg/m cube through a tube of cross -section area of 4 cm square through a height of 5 m with a speed of 40 cm/s.Find the power of engine
Asked by ayan1.chatterjee | 13 Jan, 2021, 12:05: PM
answered-by-expert Expert Answer
Pressure P at delivering side of engine , P = ρ g h 
 
where ρ is density of fluid , g is acceleration due to gravity and h is height 
 
Pressure P = 1200 × 9.8 × 5 = 58800 Pa
 
Force F exerted by engine to make the fluid to flow through the tube, F  = Pressure × area of crosssection of tube
 
Force F = 58800 × 4 × 10-4 = 23.52 N
 
Power delivered by engine = force × speed of fluid = 23.52 × 0.4 = 9.41 W
Answered by Thiyagarajan K | 13 Jan, 2021, 12:39: PM

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CBSE 9 - Physics
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