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CBSE Class 8 Answered

ABCDE is a regular pentagon.Diagonals AD divides (angle CDE)  into two parts . Find the ratio of ( angle ADE/angle ADC)       ANS -   1:2
Asked by Mohdayaz9921 | 30 Dec, 2018, 06:52: AM
answered-by-expert Expert Answer
Figure shows the regular pentagon, with diagonal AD divides begin mathsize 12px style angle end styleCDE into two parts.
Interior angle θ of regular pentagon :- (n-2)×180 = n×θ , where n = 5 is number of sides of pentagon
 
hence we get θ = 108° as shown in figure for begin mathsize 12px style angle end styleBCD. 
Diagonal AD is parallel to side BC. Hence begin mathsize 12px style angle end styleADC = 180-108 = 72°
begin mathsize 12px style angle end styleADE = 108 - begin mathsize 12px style angle end styleADC = 108-72 = 36°
hence begin mathsize 12px style angle end styleADE : begin mathsize 12px style angle end styleADC = 36 : 72 = 1 : 2
Answered by Thiyagarajan K | 30 Dec, 2018, 07:58: AM
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