CBSE Class 8 Answered
The four integers consecutively lower than 81 ,and the four consecutively higher than 81are added together . this sum is divisible by
Asked by sarkarchaitali4001 | 02 May, 2024, 04:11: PM
Expert Answer
Four integers consecutively lower than 81 are 80, 79, 78, 77
Four integers consecutively more than 81 are 82, 83, 84, 85
Required sum = 80 + 79 + 78 + 77 + 82 + 83 + 84 + 85
= (80 + 82) + (79 + 83) + (78 + 84) + (77 + 85)
= (81 + 81) + (81 + 81) + (81 + 81) + (81 + 81)
= 8 x 81
= Divisible by 81, 9, 3, 8, 4, 2
Answered by Rashmi Khot | 02 May, 2024, 06:32: PM
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