CBSE Class 11-science Answered
A particle of unit mass undergoes one dimensional motion such that its velocity varies according to v(x) = bx-2n, where b and n are constants and x is the position of the particle. Find acceleration as a function of x
Asked by tps.mjmdr | 02 Jun, 2018, 11:09: AM
Expert Answer
velocity function v(x) = b×x - 2n
acceleration a(x) = dv/dt = b× (dx/dt) = b×v(x) = b×{b×x - 2n) = b2×x-2×b×n
Answered by Thiyagarajan K | 04 Jun, 2018, 02:57: PM
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