CBSE Class 8 Answered
A convex lens of N =1.5 and focal length 0.2m is immersed in water of R.I.=1.33..calculate the change in power of the lens
Asked by ampoluharitha | 28 Dec, 2018, 08:53: PM
Expert Answer
Initial Power of lens = 1/0.2 = 5 Diopter
let us get the radius of curvature of the given lens from lens makers formula :
where f is focal length, μ is refractive index, Rs are radii of curvature.
from (1), by substituting values for f and μ, we get, ....................(2)
when the lens is immersed in liquid, refractive index becomes = 1.5/1.33 = 1.128
hence power of lens when it is immersed in liquid, using eqns.(1) and (2) : (1.128-1)×10 = 1.28 Diopter
Change in power = 5 -1.28 = 3.72 Diopter
Answered by Thiyagarajan K | 29 Dec, 2018, 09:13: AM
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