CBSE Class 12-science Answered
A charge q is enclosed by a spherical surface of radius R.If the radius is reduced to half,how would the electric flux through the surface change?
Asked by ankush76728 | 06 May, 2024, 04:52: PM
Expert Answer
Total flux through the closed surface will not change . But flux density will be increased if radius of sphere is halved.
Flux density is magnitude of electric field E .
Initial Flux density over the closed surface of sphere of radius R is
| E | = q / [ ( 4πεo ) R2 ]
If the radius is halved , then flux density
|E1 | = (4q) / [ ( 4πεo ) R2 ]
Answered by Thiyagarajan K | 06 May, 2024, 11:34: PM
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