Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

A bullet initially moving with a velocity of 20m/s strikes a target and comes to rest after penetrating a distance of 10cm in the target. Calculate the retardation caused by the target.

Asked by manhas 14th June 2016, 8:05 PM
Answered by Expert
Answer:
Given: Initial velocity, u = 20 m/s ; Final velocity, v = 0 m/s and s = 10 cm = 0.1 m
We use the third equation of motion: v2 = u2 + 2as
→ 0 = (20)2 + 2 × a × 0.1
→ 400 =  – 0.2a
→a = –2000 m/s2
This is the acceleration of the bullet.
The reatrdation is the negative value of the acceleration.
Thus, the retardation of the bullet is 2000 m/s2
Answered by Expert 15th June 2016, 9:24 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Free related questions

Latest Questions

CBSE VIII Social Studies
Asked by Saqlainzaidi097 23rd September 2018, 9:06 PM
CBSE VII History
Asked by familyofsaji 23rd September 2018, 8:40 PM

Chat with us on WhatsApp