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# CBSE Class 9 Answered

A force acts for 10 secs on a stationary body of mass 100kg after which the force ceases to act. The body moves through a distance of 100m in the next 5 secs. Calculate:- i) the velocity acquiured by the body ii) the acceleration producced by the force iii) the magnitude of the force
Asked by atmojyotibarman7 | 30 Jul, 2021, 03:27: PM
Let us assume the body moves with constant velocity after the force cease to act

Velocity after the force cease to act = distance / time = 100 m / 5 s = 20 m/s

Velocity v after 10 second is 20 m/s and the body starts from rest , then acceleration a is determined from following equation

v = ( a × t )

acceleration  a = v / t = 20 /10 = 2 m/s2

Force = mass × acceleration = 100 × 2 = 200 N
Answered by Thiyagarajan K | 30 Jul, 2021, 03:49: PM

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