use the below v-t graph calculate, (a)the acceleration of the body as it moves from 0 to A (b)the distance covered by the body from o to a c THE acceleration of the body from B TO C

Asked by vikaashrajan11 | 28th Jul, 2021, 09:55: PM

Expert Answer:

Part (a) 
 
Acceleration = ( vf - vi ) / Δt
 
when the body moves from O to A ,  vf = 4 m/s  , vi = 0 m/s and Δt = 4 s
 
Acceleration = 4 / 4 = 1 m/s2 
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Part (b)
 
As per text , distance covered from O to A is area under the part of the curve O to A .
 
Area under O to A is area of triangle .
 
Hence distance covered = (1/2) × 4 × 4 = 8 m
 
As per figure , distance covered from A to B is area under the part of the curve A to B .
 
Area under A to B is area of rectangle .
 
Hence distance covered = 4 × 6 = 24 m
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Part (c)

Acceleration = ( vf - vi ) / Δt
 
when the body moves from B to C ,  vf = 0 m/s  , vi = 4 m/s and Δt = 6 s
 
Acceleration = -4 / 6 = -2/3 m/s2 = -0.667 m/s2


Answered by Thiyagarajan K | 28th Jul, 2021, 11:19: PM