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use the below v-t graph calculate, (a)the acceleration of the body as it moves from 0 to A (b)the distance covered by the body from o to a c THE acceleration of the body from B TO C

Asked by vikaashrajan11 | 28 Jul, 2021, 09:55: PM
Part (a)

Acceleration = ( vf - vi ) / Δt

when the body moves from O to A ,  vf = 4 m/s  , vi = 0 m/s and Δt = 4 s

Acceleration = 4 / 4 = 1 m/s2
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Part (b)

As per text , distance covered from O to A is area under the part of the curve O to A .

Area under O to A is area of triangle .

Hence distance covered = (1/2) × 4 × 4 = 8 m

As per figure , distance covered from A to B is area under the part of the curve A to B .

Area under A to B is area of rectangle .

Hence distance covered = 4 × 6 = 24 m
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Part (c)

Acceleration = ( vf - vi ) / Δt

when the body moves from B to C ,  vf = 0 m/s  , vi = 4 m/s and Δt = 6 s

Acceleration = -4 / 6 = -2/3 m/s2 = -0.667 m/s2

Answered by Thiyagarajan K | 28 Jul, 2021, 11:19: PM

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