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CBSE Class 11-science Answered

A ball is dropped from a height of 20m and rebounds with a velocity which is 3/4 of the velocity with which it hits the ground. What is the time interval the first and second bounces ( g = 10m/s^2)
Asked by shyamalimaborthakur89498 | 05 Aug, 2018, 12:34: PM
answered-by-expert Expert Answer
If the ball is dropped from height h above the ground, then it reaches the ground with speed begin mathsize 12px style v space equals space square root of 2 cross times g cross times h end root end style
if it rebounds with (3/4)th of its velocity, then time taken t to reach maximum height after first bounce is given by
t begin mathsize 12px style equals space fraction numerator 3 over 4 square root of 2 g h end root over denominator g end fraction space equals space 3 over 4 square root of fraction numerator 2 cross times h over denominator g end fraction end root space equals space 3 over 4 square root of fraction numerator 2 cross times 20 over denominator 10 end fraction end root space equals space 3 over 2 s end style
the ball will take same time to reach the ground just before second rebounce.
 
Hence the time interval between first and second rebounce is 3 seconds.
Answered by Thiyagarajan K | 05 Aug, 2018, 03:54: PM
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